In $\triangle PAT,$ $\angle P=36^{\circ},$ $\angle A=56^{\circ},$ and $PA=10.$ Points $U$ and $G$ lie on sides $\overline{TP}$ and $\overline{TA},$ respectively, so that $PU=AG=1.$ Let $M$ and $N$ be the midpoints of segments $\overline{PA}$ and $\overline{UG},$ respectively. What is the degree measure of the acute angle formed by lines $MN$ and $PA?$ $\textbf{(A) } 76 \qquad$ $ \textbf{(B) } 77 \qquad$ $ \textbf{(C) } 78 \qquad$ $ \textbf{(D) } 79 \qquad$ $ \textbf{(E) } 80$