Problem 111

{{searchResults.length}} results for “{{searchWords}}” No results found for “{{searchWords}}” × back to contents

§{{x[0]}} {{x[1]}}

Table of Contents

Problem 111: (2005 AMC 10a, 25)

In $ABC$ we have $AB = 25$, $BC = 39$, and $AC=42$. Points $D$ and $E$ are on $AB$ and $AC$ respectively, with $AD = 19$ and $AE = 14$. What is the ratio of the area of triangle $ADE$ to the area of the quadrilateral $BCED$? $\mathrm{(A) \ } \frac{266}{1521}\qquad$ $ \mathrm{(B) \ } \frac{19}{75}\qquad$ $ \mathrm{(C) \ } \frac{1}{3}\qquad$ $ \mathrm{(D) \ } \frac{19}{56}\qquad$ $ \mathrm{(E) \ } 1$

Solution

Exercise 111: Solution

In $\triangle ABC$ we have $AB=13$, $BC=15$, and $AC=14$. Points $D$ and $E$ are on $AB$ and $AC$ respectively, with $AD=6$ and $AE=7$. What is the ratio of the area of triangle $ADE$ to the area of the quadrilateral $BCED$?

Search Go to Prev Next

Contact Us