Sign in
← Theorem 2 →
« Prev Next »
Search
Go to
{{searchResults.length}} results for “{{searchWords}}” No results found for “{{searchWords}}” × back to contents
Table of Contents

Browse by chapter, year or number

  1. Similar Triangles
  2. areas
  3. pythagoreanTheorem
  4. circles
  5. quadrilaterals
  6. threeDimensionalGeometry
  7. trigonometry
  8. conic
  9. miscellaneous
  10. exercises solutions
Theorem 2
For triangles $ABC$ and $XYZ$, if $AB=XY, AC=XZ, \angle A=\angle X$, then $\triangle ABC\cong \triangle XYZ$.
← Back to Problem 351
Search Go to Prev      Next

Contact Us

Thanks! Your message has been sent.